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1855. Maximum Distance Between a Pair of Values

You are given two non-increasing 0-indexed integer arrays nums1 and nums2.

A pair of indices (i, j), where 0 <= i < nums1.length and 0 <= j < nums2.length, is valid if both i <= j and nums1[i] <= nums2[j]. The distance of the pair is j - i.

Return the maximum distance of any valid pair(i, j). If there are no valid pairs, return0.

An array arr is non-increasing if arr[i-1] >= arr[i] for every 1 <= i < arr.length.

Example 1:

Input: nums1 = [55,30,5,4,2], nums2 = [100,20,10,10,5] Output: 2 Explanation: The valid pairs are (0,0), (2,2), (2,3), (2,4), (3,3), (3,4), and (4,4). The maximum distance is 2 with pair (2,4). 

Example 2:

Input: nums1 = [2,2,2], nums2 = [10,10,1] Output: 1 Explanation: The valid pairs are (0,0), (0,1), and (1,1). The maximum distance is 1 with pair (0,1). 

Example 3:

Input: nums1 = [30,29,19,5], nums2 = [25,25,25,25,25] Output: 2 Explanation: The valid pairs are (2,2), (2,3), (2,4), (3,3), and (3,4). The maximum distance is 2 with pair (2,4). 

Constraints:

  • 1 <= nums1.length, nums2.length <= 105
  • 1 <= nums1[i], nums2[j] <= 105
  • Both nums1 and nums2 are non-increasing.

Solutions (Python)

1. Solution

importbisectclassSolution: defmaxDistance(self, nums1: List[int], nums2: List[int]) ->int: ret=0foriinrange(len(nums1)): j=bisect.bisect_right( nums2, False, key=lambdax: x<nums1[i]) -1ret=max(ret, j-i) returnret
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